algebra help

[margot]

ok nvm I am smart now.

Edited December 18, 2005 by Lindsay

[Anime Gee]

( ^o^) <3

[margot]

wait, no I need help on this problem.

5g + 9 = 2(g + 3)

5g+9 = 2g + 6

-9 -9

5g = 2g + -3

-5g -5g

-3g = -3

-3g/-3 = -3/-3

g = -1

is that right, seems weird. (i'm doing identities)

Edited December 18, 2005 by Lindsay

[Arcane]

Edit: ^ looks right to me

Solving for g, right?

5g+9=2(g+3)

5g+9=2g+6

subtract 2g from both sides

3g+9=6

subtract 9 from both sides

3g=-3

g=-1

Edited December 18, 2005 by Arcane

[margot]

waitt, sry XDD this one is hard.

4(k+2) - 4 = 2k

???? wtf

[Anime Gee]

Excellent work! (^o^ ) <3

[Anime Gee]

waitt, sry XDD this one is hard.

4(k+2) - 4 = 2k

???? wtf

Ah!

4K + 8 - 4 = 2k

4K + 4 = 2K

4K - 2K = - 4

2K = - 4

K= - 2

( ^o^) <3

[Suga Babe]

Ah!

4K + 8 - 4 = 2k

4K + 4 = 2K

4K - 2K = - 4

2K = - 4

K= - 2

( ^o^) <3

yup, yup...easy enough.

[margot]

Ah!

4K + 8 - 4 = 2k

4K + 4 = 2K

4K - 2K = - 4

2K = - 4

K= - 2

( ^o^) <3

i was going to do that but, doesn't subtracting 2k from 4k go against order of operations, like left to right not right to left.

[Anime Gee]

i was going to do that but, doesn't subtracting 2k from 4k go against order of operations, like left to right not right to left.

It doesn't matter. You can do it anyway you want, so long as you have the correct answer in the end! (^o^ ) <3 <3

[Suga Babe]

i was going to do that but, doesn't subtracting 2k from 4k go against order of operations, like left to right not right to left.

no...because you bring the 2K over from the right side...and its positive there, so when you bring it over it becomes a negative.

[Anime Gee]

4K + 8 - 4 = 2k

4K + 4 = 2K

4K - 2K = - 4

2K = - 4

K= - 2

OR

4K + 8 - 4 = 2k

4K + 4 = 2K

4 = - 4K + 2K

4 = - 2K

-2 = K

( ^o^) <3

[margot]

oh ok.

one more, sorry:::

"The ratio of the number of girls in school to the number of boys is 8 : 7. If there are 378 boys in school, how many girls are in school?"

is the answer 432 ????

Edited December 18, 2005 by Lindsay

[JesusTheNinja]

Yep, 432.

[Suga Babe]

Yep, 432.

ditto

edit: hahah...i just noticed my post count...man...i should stop posting now lol

[Gundampilotspaz]

waitt, sry XDD this one is hard.

4(k+2) - 4 = 2k

???? wtf

4(k+2) - 4 = 2k

4K + 8 - 4 = 2K

4K + 4 = 2K

2K = -4

K = -2

Edit: damn I was a bit late, I'm playing EVE Online! give me a break

Edited December 18, 2005 by Grand Magus Salvarus

[margot]

okay I really don't get this kind of problem:

x = y-z over 5

solve for y

[Anime Gee]

okay I really don't get this kind of problem:

x = y-z over 5

solve for y

You need to isolate the y.

Are you sure that's the problem? Seems like it's missing info.

I want to say that the answer goes something like this:

- 5 / Z + X = Y

I'll have to refer to my math book.

[margot]

nope.

it says

"solve the equation for the given variable"

x = y-z over 5

[Anime Gee]

Hmmm....

I'm stumped here. Hahahaha!

You probably have to isolate the 5.

- Y + Z + X = 5

[JesusTheNinja]

I can't tell what the question is. is it: x=(y-z)/5 or x=y-(z/5) ?

The first is y=5x+z, and the second is y=x+(z/5).

[margot]

is the exact problem.

solve for y

Edited December 18, 2005 by Lindsay

[JesusTheNinja]

x=(y-z)/5

5x=y-z

5x+z=y

y=5x+z

[darkon]

Beaten to it.

Edited December 18, 2005 by Marcus Aurelius

[Gundampilotspaz]

Well you solved for b-c, it says solve for b.