margot Posted July 28, 2007 Share Posted July 28, 2007 posted here since no one visits homowork and the last thread was here anyway Link to post

Siendra Posted July 28, 2007 Share Posted July 28, 2007 Split it into four triangles, four rectangles, and a square. Work out the area's of each independently, and add them together. Or draw a square around the entire Octagon. Then use 52.4176 and subtract the area of the four triangles you create on each corner (They're right triangles where H=3 Edit: and B=2.12). Link to post

Siendra Posted July 28, 2007 Share Posted July 28, 2007 Oh, yeah. With the way that's set-up, the simplest way is: A = (3.62*1.5/2)*16 Yikes. I haven't been in a math class for... 16 or 17 months... >.< Link to post

Samurai Drifter Posted September 2, 2007 Share Posted September 2, 2007 For the first problem set, I think #3 is possible given that the interior lines intersect exactly halfway (I forgot the math terminology...). From there you could find the length of the hypotenuse and then multiply that by 4. But that's a long complicated process so I'm not doing it to see what the actual answer is. Link to post

Satan Posted September 2, 2007 Share Posted September 2, 2007 I'm not used to their labeling style, and really haven't done any geometry in years. That said, I'd go with answer b WU/VU=XU/YU, and angle U os obviously congruent to itself. Link to post

margot Posted September 2, 2007 Author Share Posted September 2, 2007 do you mean answer B as in "similar by SAS"? Link to post

Satan Posted September 3, 2007 Share Posted September 3, 2007 yes in all multiple choice questions, I automatically think of the answers as a, b, c, and d Link to post

Satan Posted September 3, 2007 Share Posted September 3, 2007 assuming the "~" means similar (I think it does, but we never did too many similarity problems) then KE/FA=KI/FL=5/3 12/FL=5/3 FL*5=12*36 FL=36/5 A (i can't remember why, but I think that LZM=OZN) Link to post

Satan Posted September 4, 2007 Share Posted September 4, 2007 this one is really easy once you realize that you don't need to know much geometry. The only reason they'd give you the numbers they do is if the triangles are similar, so its just a few proportions 24/9=NM/30 NM=80 24/9=NL/24 NL=64 Link to post

Arcane Posted September 5, 2007 Share Posted September 5, 2007 For 26.) the two triangles are similar, so you can setup a ratio of the big triangle's perimeter to AC and set that equal to x (the small triangle's perimeter) to DF, so that: 72/22 = x/14 solve for x and you get 45.82 For 27.) I think the ratio 6/5 carries through for the entire triangle, since as far as I can tell they're similar. So I believe you can just multiply 6/5 by the smaller triangle's area to get the larger triangle's area, which results in 90 cm^2. It's been a long time since I've done geometry though, so I may be wrong. Link to post

Satan Posted September 14, 2007 Share Posted September 14, 2007 432= 144*3 so root(432)= root (144*3)=root(144)*root(3)=12root(3) sorry if that's hard to understand (or too late) Link to post

## Recommended Posts

## Please sign in to comment

You will be able to leave a comment after signing in

Sign In Now